Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Consider a reaction A (g) ⎯→ 3 B (g) + 2C (g) with rate constant 1.386 × 10 –2 min –1 . Starting with 2 moles of A in 12.5 litre vessel, if reaction is allowed to takes place at constant pressure & at 298 K then find the concentration of B after 100 min -
Text Solution
Verified by ExpertsThe correct answer is:
C
K = 
or t 1/2 = 
= 50 min
A (g) ⎯→ 3B (g) + 2C (g)
after 2 – x 3x 2x
100 min = 0.5 4.5 3
= 
⇒ V f = 
× 12.5 ⇒ 50 Lit
∴ Concentration of B after
100 min = 
= 0.09 M
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